Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minQB

ChemistryMediummultiple choice

Which of the following is/are correct :

Answer:

A, B, D

Solution:

(A) Weight of $A l^{3 +}$ in 100 mL solution $= 100 \times 27 = 2.7 g$ .

$2 m o l A l^{3 +} (27 \times 2 g) = 1 m o l A l_{2} (S O_{4})_{3} \cdot 18 H_{2} O = 666 g$

$2.7 g$ of $A l^{3 +} = \frac{666 \times 2.7}{54} = 33.3 g$

(B) Moles of $C r^{3 +} = \frac{26}{52} = 0.5 m o l$

Weight of $C r C l_{3} \cdot 6 H_{2} O = 0.5 m o lC r^{3 +} \times 266.5 = 133.25 g$

(D) Weight of $N H_{3} = 0.8 \times \frac{20}{100} = 0.16 g m L^{- 1}$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: QB

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