Chemistry - Concentration Terms Question with Solution | TestHub
ChemistryConcentration TermsVolume StrengthEasy2 minQB
ChemistryEasynumerical
One litre of a sample of ozonized oxygen at 0°C and 1 atm on passing through a solution liberated iodine which required 9 ml of a thiosulphate solution. A volume of 12 ml of a '10 volume' hydrogen peroxide solution liberated iodine from another iodide solution, which required 24 ml of the same thiosulphate solution. The volume per cent of ozone in the ozonized oxygen sample is
Answer:
9.00
Solution:
'10 volume' = 10/11.2 ≈ 0.893 M; 12 ml holds ≈ 10.7 mmol , liberating 10.7 mmol , matched by 24 ml thiosulphate. So 9 ml \equiv 9/24 × 10.7 ≈ 4.0 mmol = 4.0 mmol . volume = 4.0 × 22.4 ≈ 90 ml per litre = 9%. Ans: 9.
Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Volume Strength
⏱ 2mℹ️ Source: QB
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