Chemistry - Concentration Terms Question with Solution | TestHub

In order to remove ${\mathrm{Pb}}^{2+}$ from 10 liters of ${\mathrm{H}}_2\mathrm{O}$, $\mathrm{N}{\mathrm{a}}_2{\mathrm{H}}_2$ EDTA ($0.4\mathrm{M},100\mathrm{mL}$) is required.

$\mathrm{PbC}{\mathrm{l}}_2(aq.)+\mathrm{N}{\mathrm{a}}_2{\mathrm{H}}_2\mathrm{EDTA}\to 2NaCl+\mathrm{Pb}{\mathrm{H}}_2\mathrm{EDTA}$

Hence, the millimoles of $\mathrm{PbC}{\mathrm{l}}_2$ present in 1 liter of ${\mathrm{H}}_2\mathrm{O}$ is: