Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsTitrationEasy2 minQB
ChemistryEasysingle choice
To a 25 ml H₂O₂ solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N Na₂S₂O₃ solution. The volume strength of H₂O₂ solution is
Options:
Answer:
A
Solution:
meq I₂ = 20 x 0.3 = 6 meq = meq H₂O₂ in 25 ml, so normality of H₂O₂ = 6/25 = 0.24 N. Volume strength = 5.6 x N = 5.6 x 0.24 = 1.344, option (a).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration
⏱ 2mℹ️ Source: QB
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