Match the list (Relative atomic mass : Na = 23, K = 39, Ca = 40) : List - I List - II (I) 20% ( w / w ) solution of KOH (density of solution = 1.02 gm/mL) (P) 4.00 M (II) Solution containing 444 gm Ca

Question

Match the list (Relative atomic mass : Na = 23, K = 39, Ca = 40) :

List - I	List - II
(I) $20% (w / w)$ solution of KOH (density of solution = 1.02 gm/mL)	(P) 4.00 M
(II) Solution containing $444 gm CaCl_{2}$ in a 1 L solution	(Q) 3.64 M
(III) Volume of $1.204 \times 1 0^{24}$ molecules of water at $4^{\circ} C$	(R) 5 mL
(IV) Volume of 0.2 M NaOH solution containing 40 mg of NaOH	(S) 36 mL

The correct match is :

TestHub · Accepted Answer

(P) 20 gm of KOH present in 100 gm solution.

$V = \frac{100}{1.02} = 98.04 m l$

$M = \frac{20/56}{98.04} = 3.64 M$

(Q) 444 gm CaCl₂ in 1 liter solute.

Molarity $= \frac{444}{111/1} = 4 M$

(R) $1.204 \times 1 0^{24}$ molecules of water = 2 mole.

2 mole of water at 4°C is 36 gm or 36 ml.

(S)

Volume of 0.2 M NaOH solution.

$0.2 \times V = 1 \times 1 0^{- 3} m o l e$

$V = \frac{1 \times 1 0 ^{- 3}}{0.2} \times 1000$

$V = 5 m l$

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