Sodium oxide reacts with water to produce sodium hydroxide. $20.0 g$ of sodium oxide is dissolved in $500 mL$ of water. Neglecting the change in volume, the concentration of the resulting $NaOH$ solution is _________ $\times 10^{- 1} M .$ (Nearest integer)
[Atomic mass : $Na = 23.0, O = 16.0, H = 1.0$ ]

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Na 2 O + H 2 O → 2 NaOH According to reaction 20 62 mole of Na 2 O gives 40 62 mole of NaOH so molarity of NaOH solution is = n NaOH V ml × 1000 = 40 62 × 1000 500 = 80 62 = 1 . 29 M ≈ 1 . 3 M

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