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Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minPYQ_2019

ChemistryMediumassertion reason

$8 g$ of $NaOH$ is dissolved in $18 g$ of $H_{2} O$ . Mole fraction of $NaOH$ in solution and molality (in $mol {kg}^{- 1}$ ) of the solution respectively are:

Options:

Answer:

Solution:

$n_{1} = \frac{8}{40} = 0.2$
$n_{2} = \frac{18}{18} = 1$ ;
$n_{t} = n_{1} + n_{2} = 0.2 + 1 = 1.2$
Mole fraction of $N a O H = \frac{n_{1}}{n_{t}} = \frac{0.2}{1.2} = 0.167$
Molality $= \frac{8}{40} \times \frac{1000}{18} = 11.11$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2019

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