Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minPYQ_2014

ChemistryMediumassertion reason

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

Options:

Answer:

Solution:

Mass of compound $= 120 g; m o l e s = \frac{120 g}{60 g / m o l e} = 2$

Mass of solution $= 1000 + 120 = 1120 g$

Volume of solution $\frac{m a s s}{d} = \frac{1120 g}{1.12 g / m L} = 1000 m L$

Molarity $= \frac{2 moles}{1000 mL} \times 1000 mL$

= 2 M (no of moles/Litre)

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2014

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