Chemistry - Concentration Terms Question with Solution | TestHub

2.5 L $1\mathrm{M}$ Naoh with 3 L $0.5\mathrm{M}$ $\mathrm{NaOH}$. Intially, Number of moles in $2.5\mathrm{L}$, $\begin{array}{rl}1\mathrm{M}\mathrm{NaOH}& =2.5\times 1\\ & =2.5\text{ moles }\end{array}$ Number of moles in $3\mathrm{L},0.5\mathrm{M}\mathrm{NaOH}$ $=3\times 0.5=1.5$ moles. $\Rightarrow$ Total number of moles in final mixture $=2.5+1.5=4.0$ moles . The total volume of solution $=2.5+3=5.5\mathrm{L}$ $\begin{array}{rl}& \Rightarrow \text{ Molarity of final solution }=\frac{4}{5.5}\\ & =0.728\mathrm{M}\end{array}$