Chemistry - Complete s-block Question with Solution | TestHub

The reaction is:

${\mathrm{CaCO}}_3(\mathrm{s})+2\mathrm{AcOH}(\mathrm{aq})\stackrel{{\mathrm{Na}}_2{\mathrm{C}}_2{\mathrm{O}}_4\text{ solution }}{\to }\mathrm{Ca}(\mathrm{OAc}{)}_2(\mathrm{aq})+{\mathrm{H}}_2\mathrm{O}(\mathrm{l})+{\mathrm{CO}}_2(\mathrm{g})$

In the presence of ${\mathrm{Na}}_2{\mathrm{C}}_2{\mathrm{O}}_4$ solution, the ${\mathrm{Ca}}^{2+}$ ions from $\mathrm{Ca}(\mathrm{OAc}{)}_2$ will react with oxalate ions (${\mathrm{C}}_2{\mathrm{O}}_4^{2-}$) to form calcium oxalate (${\mathrm{CaC}}_2{\mathrm{O}}_4$), which is insoluble and precipitates as a white solid.

Therefore, the product ${\mathrm{CaC}}_2{\mathrm{O}}_4$ will be precipitated as a white ppt.