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ChemistryComplete s-blocks-block IAMedium2 minQB

ChemistryMediumsingle choice

Which compound will liberate oxygen when react with $H_{2} O -$

Options:

Answer:

Solution:

Option 2 is correct. Potassium superoxide ( $K O_{2}$ ) reacts with water to liberate oxygen gas. The reaction is:

$4 K O_{2} (s) + 2 H_{2} O (l) ⟶ 4 K O H (a q) + 3 O_{2} (g)$

Other options like $N a_{2} O_{2}$ and $C s_{2} O_{2}$ are peroxides and produce $H_{2} O_{2}$ and $O_{2}$ upon reaction with water, but $K O_{2}$ is a superoxide and produces more $O_{2}$ . $N a_{2} O$ is a normal oxide and produces no $O_{2}$ .

Stream:JEESubject:ChemistryTopic:Complete s-blockSubtopic:s-block IA

⏱ 2mℹ️ Source: QB

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