Chemistry - Complete s-block Question with Solution | TestHub

Reaction at $0^{\circ }C$: $N{a}_2{O}_2+2H_{2}O\to 2NaOH(P)+H_2{O}_2(Q)$

Reaction at $25^{\circ }C$: $2N{a}_2{O}_2+4H_{2}O\to 4NaOH(P)+O_2\uparrow (R)+2H_{2}O(S)$

Bond order in Q ($H_2{O}_2$): The single covalent bond between the identical atoms ($O-O$) has a bond order of 1.

Bond order in R ($O_2$): The double covalent bond between the identical atoms ($O=O$) has a bond order of 2.

Total Sum: $BondOrde{r}_Q+BondOrde{r}_R=1+2=3$.