In the ammonia-soda (Solvay) process, consider these steps (ignore balancing where needed): 2A + B + C → D ; D + B + C → 2E ; E + NaCl → F + G ↓ ; G Δ H + C + B . F reacts with calcium hydroxide to

Question

In the ammonia-soda (Solvay) process, consider these steps (ignore balancing where needed):

$2A + B + C \to D$ ;

$D + B + C \to 2E$ ;

$E + NaCl \to F + G ↓$ ;

$G Δ H + C + B$ .

F reacts with calcium hydroxide to regenerate A, forming calcium chloride and B.

To obtain exactly $106 g$ of H, some G is calcined. The quantity of F formed along with this G in the E-plus-sodium-chloride step is then treated with calcium hydroxide.

Find the sum of the number of moles of G calcined and the number of moles of calcium hydroxide consumed.

Use atomic masses: $Na = 23$ , $C = 12$ , $O = 16$ , $H = 1$ .

TestHub · Accepted Answer

H is N a 2 ​ C O 3 ​ , so 106 g is 1 mol . Calcination follows: 2NaHC O 3 ​ → N a 2 ​ C O 3 ​ + C O 2 ​ + H 2 ​ O . Thus G is 2 mol of sodium hydrogencarbonate. F is ammonium chloride, formed in a 1 : 1 mole ratio with G. Hence F is also 2 mol . Two moles of ammonium chloride consume one mole of calcium hydroxide in ammonia recovery. The required sum is 2 + 1 = 3 .

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