Chemistry - Complete s-block Question with Solution | TestHub

The reaction is $4{\mathrm{KO}}_2+2{\mathrm{CO}}_2\to 2{\mathrm{K}}_2{\mathrm{CO}}_3+3{\mathrm{O}}_2$.

Thus, P is ${\mathrm{K}}_2{\mathrm{CO}}_3$ (solid) and Q is ${\mathrm{O}}_2$ (gas).

The molecular orbital configuration of ${\mathrm{O}}_2$ is $\mathrm{KK}({\sigma }_{2s}{)}^2({\sigma }_{2s}^{\ast }{)}^2({\sigma }_{2p_z}{)}^2({\pi }_{2p_x}{)}^2({\pi }_{2p_y}{)}^2({\pi }_{2p_x}^{\ast }{)}^1({\pi }_{2p_y}^{\ast }{)}^1$.

The total number of electrons in antibonding molecular orbitals (ABMOs) is $2({\sigma }_{2s}^{\ast })+2({\pi }_{2p_x}^{\ast })+2({\pi }_{2p_y}^{\ast })=6$.