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ChemistryComplete s-blocks-block IAMedium2 minQB

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Sodium carbonate solution in $H_{2} O$ is alkaline due to-

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Solution:

Sodium carbonate ( $N a_{2} C O_{3}$ ) is a salt of a strong base ( $N a O H$ ) and a weak acid ( $H_{2} C O_{3}$ ). When dissolved in water, it dissociates into $N a^{+}$ and $C O_{3}^{2 -}$ ions. The $N a^{+}$ ion is a conjugate acid of a strong base and does not hydrolyze. The $C O_{3}^{2 -}$ ion is the conjugate base of a weak acid and hydrolyzes to produce $O H^{-}$ ions, making the solution alkaline.

The hydrolysis reaction is:

$C O_{3}^{2 -} (a q) + H_{2} O (l) ⇌ H C O_{3}^{-} (a q) + O H^{-} (a q)$

Stream:JEESubject:ChemistryTopic:Complete s-blockSubtopic:s-block IA

⏱ 2mℹ️ Source: QB

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