Chemistry - Complete s-block Question with Solution | TestHub

The reaction of sodium peroxide ($N{a}_2{O}_2$) with sulfur dioxide ($S{O}_2$) in an aqueous solution involves two steps. First, $N{a}_2{O}_2$ reacts with water to form $NaOH$ and hydrogen peroxide ($H_2{O}_2$). Then, $S{O}_2$ reacts with $NaOH$ to form sodium sulfite ($N{a}_{2}S{O}_3$), which is further oxidized by $H_2{O}_2$ to sodium sulfate ($N{a}_{2}S{O}_4$).

Step 1: Reaction of $N{a}_2{O}_2$ with water

$$N{a}_2{O}_2(s)+2H_{2}O(l)\to 2NaOH(aq)+H_2{O}_2(aq)$$

Step 2: Reaction of $S{O}_2$ with $NaOH$

$$S{O}_2(g)+2NaOH(aq)\to N{a}_{2}S{O}_3(aq)+H_{2}O(l)$$

Step 3: Oxidation of $N{a}_{2}S{O}_3$ by $H_2{O}_2$

$$N{a}_{2}S{O}_3(aq)+H_2{O}_2(aq)\to N{a}_{2}S{O}_4(aq)+H_{2}O(l)$$

Combining these steps, the overall reaction leads to the formation of sodium sulfate ($N{a}_{2}S{O}_4$).

The final compound formed is $N{a}_{2}S{O}_4$.