Chemistry - Complete s-block Question with Solution | TestHub

Let oxidation number of Rb as x
$\underset{2\mathrm{x}-2=0}{\mathrm{R}{\mathrm{b}}_2\mathrm{O}}\to \mathrm{x}=+1$
$\underset{2\mathrm{x}-2=0}{\mathrm{R}{\mathrm{b}}_2{\mathrm{O}}_2}\left(\mathrm{p}\mathrm{e}\mathrm{r}\mathrm{o}\mathrm{x}\mathrm{i}\mathrm{d}\mathrm{e}\right)\to \mathrm{x}=+1$
In peroxide oxidation number of oxygen is taken as$-1$
$\underset{2\mathrm{x}-2=0}{\mathrm{R}\mathrm{b}{\mathrm{O}}_2}\left(\mathrm{s}\mathrm{u}\mathrm{p}\mathrm{e}\mathrm{r}\mathrm{o}\mathrm{x}\mathrm{i}\mathrm{d}\mathrm{e}\right)\to \mathrm{x}=+1$
In superoxide oxidation number of oxygen is taken as$-\frac{1}{2}$