Be 2 C + 4 H 2 O ⟶ 2 X + CH 4 X + 2 HCl ⟶ Y 'X' and 'Y' formed in the above two reactions are -

Be 2 C + 4H 2 O → 2 Be(OH) 2 + CH 4 Thus, 'X' is Be(OH) 2 . Next, X reacts with HCl to form: Be(OH) 2 + 2HCl → BeCl 2 + 2H 2 O Thus, 'Y' is BeCl 2 .

Chemistry - Complete s-block Question with Solution | TestHub

ChemistryComplete s-blocks-block IIAEasy2 minPYQ_2020

ChemistryEasysingle choice

Be₂C + 4 H₂O $⟶$ 2 X + CH₄

X + 2 HCl $⟶$ Y

'X' and 'Y' formed in the above two reactions are -

Answer:

Solution:

Be₂C + 4H₂O → 2 Be(OH)₂+ CH₄
Thus, 'X' is Be(OH)₂.

Next, X reacts with HCl to form:
Be(OH)₂+ 2HCl → BeCl₂+ 2H₂O
Thus, 'Y' is BeCl₂.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Complete s-blockSubtopic:s-block IIA

⏱ 2mℹ️ Source: PYQ_2020

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