Chemistry - Complete s-block Question with Solution | TestHub

Since magnesium bicarbonate on heating gives insoluble magnesium carbonate, therefore, the anion is$\mathrm{H}\mathrm{C}{{\mathrm{O}}_3}^{-}$
$\mathrm{M}\mathrm{g}\mathrm{C}{\mathrm{l}}_2+2\mathrm{N}\mathrm{a}\mathrm{H}\mathrm{C}{\mathrm{O}}_3\to \underset{\mathrm{S}\mathrm{o}\mathrm{l}\mathrm{u}\mathrm{b}\mathrm{l}\mathrm{e}}{\mathrm{M}\mathrm{g}(\mathrm{H}\mathrm{C}{\mathrm{O}}_3{)}_2}+2\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}$
$\text{Mg}{({\text{HCO}}_3)}_2\stackrel{\text{Δ}}{\to }\underset{\text{White}}{{\text{MgCO}}_3}\downarrow +{\text{H}}_2\text{O}+{\text{CO}}_2\uparrow$