Chemistry - Complete s-block Question with Solution | TestHub

During the electrolysis of aq.$\mathrm{N}{\mathrm{a}}_2\mathrm{S}{\mathrm{O}}_4,{\mathrm{H}}_2$is evolved at the cathode as${\mathrm{E}}_{\mathrm{R}.\mathrm{P}.}$of sodium (-2.71 V) is much lower than that of water (-0.83 V) while${\mathrm{O}}_2$is evolved at the anode as${{\mathrm{E}}^{\mathrm{0}}}_{\mathrm{R}.\mathrm{P}.}$potential of$\mathrm{S}{{\mathrm{O}}_4}^{2-}$ion (-0.2 V) is much more than that of water (-1.23 V).