Chemistry - Complete s-block Question with Solution | TestHub

When ${\mathrm{CO}}_2$ is passed through aqueous solution of ${\mathrm{BaO}}_2,{\mathrm{BaCO}}_3$ is precipitated and ${\mathrm{H}}_2{\mathrm{O}}_2$ is formed. ${\mathrm{BaO}}_2+{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{BaCO}}_3\downarrow +{\mathrm{H}}_2{\mathrm{O}}_2$ ${\mathrm{H}}_2{\mathrm{O}}_2$ can also be prepared by reaction of ${\mathrm{H}}_2{\mathrm{SO}}_4$ with hydrated barium peroxide. ${\mathrm{BaO}}_2\cdot 8{\mathrm{H}}_2\mathrm{O}+{\mathrm{H}}_2{\mathrm{SO}}_4⟶{\mathrm{BaSO}}_4+8{\mathrm{H}}_2\mathrm{O}+{\mathrm{H}}_2{\mathrm{O}}_2$