Chemistry - Complete s-block Question with Solution | TestHub

When $\mathrm{Zn}$ is reacted with excess of $\mathrm{NaOH}$, sodium zincate is obtained. $$\mathrm{Zn}+2\mathrm{NaOH}+2{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{Na}}_2\left[\mathrm{Zn}(\mathrm{OH}{)}_4\right]+{\mathrm{H}}_2$$ soluble Or $$\mathrm{Zn}+2\mathrm{NaOH}⟶{\mathrm{Na}}_2{\mathrm{ZnO}}_2+{\mathrm{H}}_2$$