Chemistry - Complete Pblock- Question with Solution | TestHub
Consider the following interaction: NaF + XeF₄ → P (ionic compound)
Find the value of where: X = Value of adjacent bond angle in XeF₄ Y = Value of adjacent bond angle in the anionic part of compound 'P' Z = Maximum number of atoms that can lie in a plane in the anionic part of compound 'P'
Answer:
Solution:
The reaction is NaF + XeF₄ → Na⁺[XeF₅]⁻.
For XeF₄, Xe has 8 valence electrons. With 4 F atoms, there are 4 bonding pairs and 2 lone pairs. This corresponds to a square planar geometry, so X = 90°.
For [XeF₅]⁻, Xe has 8 valence electrons + 1 (from charge). With 5 F atoms, there are 5 bonding pairs and 1 lone pair. This corresponds to a square pyramidal geometry. The adjacent bond angle is Y = 72°.
In square pyramidal [XeF₅]⁻, all 5 F atoms and the central Xe atom can lie in a plane (the base of the pyramid). So, Z = 6.
Value = .
