Chemistry - Complete Pblock- Question with Solution | TestHub

ChemistryComplete Pblock-p-Block 13,14Medium2 minQB

ChemistryMediumsingle choice

Statement-1: $H_{3} BO_{3}$ in water behaves as a dibasic acid.

Statement-2: The ionization reaction is: $H_{3} BO_{3} + H_{2} O ⇌ B (OH)_{4}^{-}$ + $H^{+}$

Options:

Answer:

Solution:

Statement-1 is false. Boric acid, H₃BO₃, is a monobasic Lewis acid, accepting one OH⁻ from water to form B(OH)₄⁻. It does not donate H⁺ directly. Statement-2 is true, showing the correct ionization where H₃BO₃ accepts OH⁻ from H₂O, releasing H⁺ (from H₂O).

$H_{3} BO_{3} + 2 H_{2} O ⇌ B (OH)_{4}^{-} + H_{3} O^{+}$

(or simplified as in the statement)

Stream:JEESubject:ChemistryTopic:Complete Pblock-Subtopic:p-Block 13,14

⏱ 2mℹ️ Source: QB

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