Chemistry - Complete Pblock- Question with Solution | TestHub

ChemistryComplete Pblock-Miscellaneous/MixedMedium2 minQB
ChemistryMediumnumerical

Consider the following covalent compounds in their solid state and find the value of expression

N₂O₅, Cl₂O₆, PCl₅, I₂Cl₆, XeF₆, PBr₅

Where

X = Total number of compounds in which the central atom of the cationic or anionic part is sp³ hybridized.

Y = Total number of compounds having a 90° bond angle either in the cationic or anionic part.

Z = Total number of compounds having a 109°28’ bond angle either in the cationic or anionic part.

Answer:
9.00
Solution:

N₂O₅ exists as [NO₂]⁺[NO₃]⁻.

Cl₂O₆ as [ClO₂]⁺[ClO₄]⁻.

PCl₅ as [PCl₄]⁺[PCl₆]⁻.

I₂Cl₆ as [ICl₂]⁺[ICl₄]⁻.

XeF₆ as [XeF₅]⁺[F]⁻.

PBr₅ as [PBr₄]⁺[Br]⁻.

X = 3 ([NO₃]⁻, [PCl₄]⁺, [PBr₄]⁺).

Y = 3 ([PCl₆]⁻, [ICl₄]⁻, [XeF₅]⁺).

Z = 3 ([PCl₄]⁺, [PBr₄]⁺, [NO₃]⁻).

Total = X + Y + Z = 3 + 3 + 3 = 9.

Stream:JEESubject:ChemistryTopic:Complete Pblock-Subtopic:Miscellaneous/Mixed
2mℹ️ Source: QB

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