Chemistry - Complete Pblock- Question with Solution | TestHub
Consider the following covalent compounds in their solid state and find the value of expression
N₂O₅, Cl₂O₆, PCl₅, I₂Cl₆, XeF₆, PBr₅
Where
X = Total number of compounds in which the central atom of the cationic or anionic part is sp³ hybridized.
Y = Total number of compounds having a 90° bond angle either in the cationic or anionic part.
Z = Total number of compounds having a 109°28’ bond angle either in the cationic or anionic part.
Answer:
Solution:
N₂O₅ exists as [NO₂]⁺[NO₃]⁻.
Cl₂O₆ as [ClO₂]⁺[ClO₄]⁻.
PCl₅ as [PCl₄]⁺[PCl₆]⁻.
I₂Cl₆ as [ICl₂]⁺[ICl₄]⁻.
XeF₆ as [XeF₅]⁺[F]⁻.
PBr₅ as [PBr₄]⁺[Br]⁻.
X = 3 ([NO₃]⁻, [PCl₄]⁺, [PBr₄]⁺).
Y = 3 ([PCl₆]⁻, [ICl₄]⁻, [XeF₅]⁺).
Z = 3 ([PCl₄]⁺, [PBr₄]⁺, [NO₃]⁻).
Total = X + Y + Z = 3 + 3 + 3 = 9.
