Chemistry - Complete Pblock- Question with Solution | TestHub

Aqueous solution of ${\mathrm{SO}}_2$ acts as a reducing agent

$${\mathrm{SO}}_2+2{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{H}}_2{\mathrm{SO}}_4+2\mathrm{H}$$

Thus ${\mathrm{SO}}_2$ in presence of moisture is used as a reducing agent. This is due to the reducing nature of ${\mathrm{SO}}_2$. For delicate articles

$$\text{ coloured matter }+\mathrm{H}⟶\text{ colourless matter }$$ Similarly, ${\mathrm{Cl}}_2$ acts as bleaching agent in presence of moisture

$${\mathrm{Cl}}_2+{\mathrm{H}}_2\mathrm{O}⟶2\mathrm{HCl}+[\mathrm{O}]$$ coloured matter $+[\mathrm{O}]⟶$ colourless