Chemistry - Complete Pblock- Question with Solution | TestHub

Reaction 1: Reducing BF₃ with LiAlH₄ produces diborane, so compound A is B₂H₆.

Reaction 2: The hydrolysis of diborane (A) with water yields boric acid, which means compound B is H₃BO₃.

Basicity: Boric acid is a weak monobasic acid in water because it acts as a Lewis acid, accepting one OH⁻ ion rather than donating a proton.

Chemical Equation:

$$B(OH{)}_3+2H_{2}O\rightleftharpoons [B(OH{)}_4{]}^{-}+H_3{O}^{+}$$

Conclusion: Therefore, the basicity of compound B is 1.