Each numbered compound is a boron-containing compound :
B₂H₆ + CO → (1) ; B₂H₆ + NH₃ (excess, high temperature) → (2) ; B₂H₆ + NaH → (3) ; B₂H₆ + H₂O (excess) → (4)
Select the INCORRECT statement(s) according to the given information.

Question

Each numbered compound is a boron-containing compound :

B₂H₆ + CO → (1) ; B₂H₆ + NH₃ (excess, high temperature) → (2) ; B₂H₆ + NaH → (3) ; B₂H₆ + H₂O (excess) → (4)

Select the INCORRECT statement(s) according to the given information.

TestHub · Accepted Answer

(1) = BH₃←CO (B₂H₆ + 2CO), which has a dative B←C bond - (A) correct. (2) = boron nitride, BN; hexagonal BN is graphite-like in structure but is an INSULATOR (no delocalised electrons), so (B) is incorrect. (3) = NaBH₄ (B₂H₆ + 2NaH), which hydrolyses to H₂ and borate, NOT borazine - (C) is incorrect. (4) = H₃BO₃ (B₂H₆ + 6H₂O → 2H₃BO₃ + 6H₂), a weak monobasic Lewis acid - (D) correct.

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