Chemistry - Complete Pblock- Question with Solution | TestHub

$X$ is diborane ($B_2{H}_6$), which has $3c-2e^{-}$ and $2c-2e^{-}$ bonds. $B_2{H}_6$ reacts with $N{H}_3$ to give borazine ($B_3{N}_3{H}_6$), which is isostructural with benzene. At high temperatures, $B_2{H}_6$ with $N{H}_3$ produces boron nitride ($BN$). Therefore, $X=B_2{H}_6$, $Y=B_3{N}_3{H}_6$, and $Z=BN$.

$$B_2{H}_6+N{H}_3\to B_3{N}_3{H}_6$$

$$B_2{H}_6+N{H}_3\stackrel{hightemp}{\to }BN$$