C l 2 ( g ) + B a ( O H ) 2 ⟶ X ( aq. ) + B a C l 2 X + H 2 SO 4 ⟶ Y + BaSO 4 Y Δ T 365 K Z + H 2 O + O 2 Y and Z are respectively :

Question

C l 2 ​ ( g ) + B a ( O H ) 2 ​ ⟶ X ( aq. ) + B a C l 2 ​ X + H 2 ​ SO 4 ​ ⟶ Y + BaSO 4 ​ Y Δ T > 365 K ​ Z + H 2 ​ O + O 2 ​ Y and Z are respectively :

TestHub · Accepted Answer

The reaction sequence involves identifying compounds X, Y, and Z.

First, $C l_{2}$ reacts with $B a (O H)_{2}$ to form $B a C l_{2}$ and $B a (Cl O_{3})_{2}$ . Thus, X is $B a (Cl O_{3})_{2}$ .

$C l_{2} (g) + B a (O H)_{2} (a q) ⟶ B a (Cl O_{3})_{2} (a q) + B a C l_{2}$

Next, $B a (Cl O_{3})_{2}$ reacts with $H_{2} S O_{4}$ to produce $H Cl O_{3}$ and $B a S O_{4}$ . Therefore, Y is $H Cl O_{3}$ .

$B a (Cl O_{3})_{2} + H_{2} S O_{4} ⟶ 2 H Cl O_{3} + B a S O_{4}$

Finally, $H Cl O_{3}$ decomposes upon heating to give $Cl O_{2}$ , $H_{2} O$ , and $O_{2}$ . So, Z is $Cl O_{2}$ .

$2 H Cl O_{3} Δ T > 365 K 2 Cl O_{2} + H_{2} O + O_{2}$

Y and Z are $H Cl O_{3}$ and $Cl O_{2}$ respectively.

Therefore, the correct answer is B.

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