Chemistry - Complete Pblock- Question with Solution | TestHub

The reaction of $\text{NaCl}$ with concentrated ${\text{H}}_2{\text{SO}}_4$ and ${\text{MnO}}_2$ is given by:

$2\text{NaCl}+{\text{MnO}}_2+2{\text{H}}_2{\text{SO}}_4\to {\text{Na}}_2{\text{SO}}_4+{\text{MnSO}}_4+2{\text{H}}_2\text{O}+{\text{Cl}}_2$

In this reaction, the oxidation state of $\text{Mn}$ changes from $+4$ in ${\text{MnO}}_2$ to $+2$ in ${\text{MnSO}}_4$. Since the oxidation state decreases, $\text{Mn}$ undergoes reduction, not oxidation. Thus, Statement-I is incorrect.

The reaction of $\text{NaI}$ with concentrated ${\text{H}}_2{\text{SO}}_4$ and ${\text{MnO}}_2$ is given by:

$2\text{NaI}+{\text{MnO}}_2+2{\text{H}}_2{\text{SO}}_4\to {\text{Na}}_2{\text{SO}}_4+{\text{MnSO}}_4+2{\text{H}}_2\text{O}+{\text{I}}_2$

Here, the oxidation state of $\text{Mn}$ also changes from $+4$ to $+2$, which means $\text{Mn}$ undergoes reduction. Thus, Statement-II is correct.

Therefore, Statement-I is incorrect but Statement-II is correct.

Answer:Statement-Iis incorrect butStatement-IIis correct.