The order of oxidizing power among the halogens is:

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The oxidizing power of halogens depends on their standard reduction potentials ( $E^{\circ}$ ).

The standard reduction potentials for halogens are:
$F_{2} + 2 e^{-} \to 2 F^{-}$ ( $E^{\circ} = + 2.87$ V)
$C l_{2} + 2 e^{-} \to 2 C l^{-}$ ( $E^{\circ} = + 1.36$ V)
$B r_{2} + 2 e^{-} \to 2 B r^{-}$ ( $E^{\circ} = + 1.09$ V)
$I_{2} + 2 e^{-} \to 2 I^{-}$ ( $E^{\circ} = + 0.54$ V)

A higher positive value of standard reduction potential indicates a stronger tendency to accept electrons and thus a stronger oxidizing power.

Therefore, the order of oxidizing power is $F_{2} > C l_{2} > B r_{2} > I_{2}$ .

Answer: $F_{2} > Cl_{2} > Br_{2} > I_{2}$

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