Chemistry - Complete Pblock- Question with Solution | TestHub

Hydrolysis of ${\mathrm{XeF}}_4$ will give ${\mathrm{XeO}}_3$. This hydrolysis reaction is a redox reaction. This redox reaction is an example of disproportionation reaction.

$6{\mathrm{XeF}}_4+12{\mathrm{H}}_2\mathrm{O}\stackrel{}{\to }4\mathrm{Xe} + 2{\mathrm{XeO}}_3+24\mathrm{HF}+3{\mathrm{O}}_2$

The oxidation states of Xenon in the reactant and product is 

${\mathrm{XeO}}_3:\mathrm{Xe}(+6)$

${\mathrm{XeF}}_4:\mathrm{Xe}(+4)$

Hence, the difference in oxidation state is $2$.