Chemistry - Complete Pblock- Question with Solution | TestHub

Reaction of ammonia with diborane gives initially ${\mathrm{B}}_2{\mathrm{H}}_6.2{\mathrm{NH}}_3$ which is formulated as ${\left[{\mathrm{BH}}_2{\left({\mathrm{NH}}_3\right)}_2\right]}^{+} {\left[{\mathrm{BH}}_4\right]}^{-} ;$ further heating gives borazine, ${\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6$ known as ''inorganic benzene'' in view of its ring structure with alternate $\mathrm{BH}$ and $\mathrm{NH}$ groups.

$3{\mathrm{B}}_2{\mathrm{H}}_6+6{\mathrm{NH}}_3\to 3{\left[{\mathrm{BH}}_2{\left({\mathrm{NH}}_3\right)}_2\right]}^{+}{\left[{\mathrm{BH}}_4\right]}^{-}\stackrel{\mathrm{Heat}}{\to }2{\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6+12{\mathrm{H}}_2$