The number of bridged oxygen atoms present in compound $B$ formed from the following reactions is
$Pb {({NO}_{3})}_{2} \overset{673 K}{⟶} A + PbO + O_{2}$
$A \overset{Dimerise}{⟶} B$

Question

The number of bridged oxygen atoms present in compound B formed from the following reactions is Pb NO 3 2 ⟶ 673 K A + PbO + O 2 A ⟶ Dimerise B

TestHub · Accepted Answer

Thermal decomposition of lead nitrate gives nitrogen dioxide. 2 Pb NO 3 2 ⟶ Δ 673 K 2 PbO + 4 NO 2 + O 2 2 NO 2 ⟶ Dimerisation N 2 O 4

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