Chemistry - Complete Pblock- Question with Solution | TestHub

${\mathrm{B}}_2(\mathrm{C}{\mathrm{H}}_3{)}_6$cannot be prepared from${\mathrm{B}}_2{\mathrm{H}}_6$while rest all can be prepared as we have two types of hydrogens.
$\mathrm{A}.$${\mathrm{B}}_2{\mathrm{H}}_6+6{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{H}}_3\mathrm{B}{\mathrm{O}}_3+6{\mathrm{H}}_2$
$\mathrm{C}.$$2\mathrm{N}\mathrm{a}\mathrm{H}+{\mathrm{B}}_2{\mathrm{H}}_6\to 2\mathrm{N}\mathrm{a}\left[\mathrm{B}{\mathrm{H}}_4\right]$
$\mathrm{D}.$${\mathrm{B}}_2{\mathrm{H}}_6+{\mathrm{O}}_2\to {\mathrm{B}}_2{\mathrm{O}}_3+3{\mathrm{H}}_2\mathrm{O}$