When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide

Question

When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is

Options:

Answer:

D

Solution:

$2 A l + 6 H_{2} O \to 2 A l {(O H)}_{3} ↓ + 3 H_{2}$

$Al {(OH)}_{3} + NaOH \to Na [{(OH)}_{4}] (soluble)$

TestHub · Accepted Answer

2 A l + 6 H 2 O → 2 A l O H 3 ↓ + 3 H 2 Al OH 3 + NaOH → Na OH 4 soluble

Chemistry - Complete Pblock- Question with Solution | TestHub

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