Chemistry - Complete Pblock- Question with Solution | TestHub

ChemistryComplete Pblock-p-Block 13,14Easy2 minPYQ_2020

ChemistryEasysingle choice

The intermediate product (X) formed in the following reaction is

$B_{2} H_{6} + 6 N H_{3} \to 3 X \overset{h e a t}{\to} 2 B_{3} N_{3} H_{6} + 12 H_{2}$

Options:

Answer:

Solution:

$\underset{D i b o r a n e}{3 B_{2} H_{6}} + 6 N H_{3} \overset{l o w temp.}{\to} \underset{(X)}{3 {[B H_{2} {(N H_{3})}_{2}]}^{+} {[B H_{4}]}^{-}} \overset{473 K Δ}{\to} \underset{B o r a z i n e}{2 B_{3} N_{3} H_{6}} + 12 H_{2}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Complete Pblock-Subtopic:p-Block 13,14

⏱ 2mℹ️ Source: PYQ_2020

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