The products obtained from the following chemical reactions are respectively (i) NaOH ( hot and conc . ) + Cl 2 → (ii) XeF 6 ( excess ) + H 2 O →

The reactions are as follows: (i) 6 NaOH ( hot and conc . ) + 3 Cl 2 → 5 NaCl + NaClO 3 + 3 H 2 O (ii) XeF 6 ( excess ) + 3 H 2 O → XeO 3 + 6HF

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ChemistryComplete Pblock-p-Block 17,18Easy2 minPYQ_2020

ChemistryEasysingle choice

The products obtained from the following chemical reactions are respectively

(i) $\underset{(hot and conc .)}{NaOH} + {Cl}_{2} \to$

(ii) $\underset{(excess)}{{XeF}_{6}} {+ H}_{2} O \to$

Options:

Answer:

Solution:

The reactions are as follows:

(i) $\underset{(hot and conc .)}{6 NaOH} + 3 {Cl}_{2} \to 5 NaCl + {NaClO}_{3} + 3 H_{2} O$

(ii) $\underset{(excess)}{{XeF}_{6}} + 3 H_{2} O \to {XeO}_{3} + 6HF$

Stream:NTA_ABHYASSubject:ChemistryTopic:Complete Pblock-Subtopic:p-Block 17,18

⏱ 2mℹ️ Source: PYQ_2020

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