Chemistry - Complete Pblock- Question with Solution | TestHub

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$\mathrm{NaOH}$ gives ${\mathrm{NaClO}}_3$ on reaction with chlorine gas.

$\mathrm{Ca}{\left(\mathrm{OH}\right)}_2$ gives ${\mathrm{CaOCl}}_2$ on reaction with chlorine gas.

$$\begin{gathered} \underset{\left(\mathrm{hot} \mathrm{and} \mathrm{conc}\right)}{6\mathrm{NaOH}+3{\mathrm{Cl}}_2}\to \underset{\mathrm{A}}{{\mathrm{NaClO}}_3}+5\mathrm{NaCl}+3{\mathrm{H}}_2\mathrm{O} \\ \underset{\mathrm{dry}}{2\mathrm{Ca}{\left(\mathrm{OH}\right)}_2}+2{\mathrm{Cl}}_2\to \underset{\mathrm{B}}{\mathrm{Ca}{\left(\mathrm{OCl}\right)}_2}+{\mathrm{CaCl}}_2+2{\mathrm{H}}_2\mathrm{O} \end{gathered}$$

$\mathrm{Ca}{\left(\mathrm{OCl}\right)}_2$ is known as bleaching powder.