Chemistry - Complete Pblock- Question with Solution | TestHub

Bond energy ∝ Bond strength

Bond strength ∝ overlapping ∝ 1/Energy Level

F - F   Cl - Cl  Br - Br   I - I
2p-2p  3p-3p   4p-4p  5p-5p

So, the order of bond energy should be
${\text{F}}_{\text{2}}{\text{>Cl}}_{\text{2}}{\text{>Br}}_{\text{2}}{\text{>I}}_{\text{2}}$

But in case of the lower value of bond dissociation energy of fluorine is due to the high inter-electronic repulsions between non-bonding electrons in the$\text{2p-}$orbitals of fluorine. As a result,$\text{F}-\text{F}$bond is weaker in comparison to$\text{Cl}-\text{Cl}$and$\text{Br}-\text{Br}$bonds. So, the correct order of bond dissociation energy is${\text{Cl}}_{\text{2}}{\text{>Br}}_{\text{2}}{\text{> F}}_{\text{2}}{\text{>I}}_{\text{2}}$. S
oxidising character order is same as SRP value.${\text{F}}_{\text{2}}{\text{>Cl}}_{\text{2}}{\text{>Br}}_{\text{2}}{\text{>I}}_{\text{2}}$

$\text{HI>HBr>HCl>HF}$acidic character

acidic character$\propto$stability of conjugate base (Anion)

Small size atom has more electron density. So less stable hence less acidic.

$\text{F>Cl>Br>I}$electronegativity on moving left to right in a period, the tendency to gain electron increases to get inert gas configuration.