Chemistry - Complete Pblock- Question with Solution | TestHub

When a mixture of ${\mathrm{BCl}}_3$ and ${\mathrm{H}}_2$ is subjected to silent electric discharge, diborane and $\mathrm{HCl}$ are formed. Diborane reacts with ${\mathrm{NH}}_3$ at $200°\mathrm{C}$ to give Borazine (inorganic benzene).

$2{\mathrm{BCl}}_3+6{\mathrm{H}}_2\underset{\mathrm{discharge}}{\overset{\mathrm{Electric}}{\to }}\underset{\left(\mathrm{x}\right)}{{\mathrm{B}}_2{\mathrm{H}}_6}+6\mathrm{HCl}$

$\underset{1}{3{\mathrm{B}}_2{\mathrm{H}}_6}+\underset{2}{6{\mathrm{NH}}_3}\stackrel{200°\mathrm{C}}{⟶}\underset{\mathrm{Borazine}\left(\mathrm{y}\right)}{2{\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6}+12{\mathrm{H}}_2$