Chemistry - Complete Pblock- Question with Solution | TestHub

(i)  ${\mathrm{HClO}}_4\mathrm{ }\rightleftharpoons {\mathrm{H}}^{+}+{\mathrm{ClO}}_4^{-\mathrm{ }}$

${\mathrm{ClO}}_4^{-}$  is resonance stabilized anion.

$\mathrm{HClO}\mathrm{ }\rightleftharpoons {\mathrm{H}}^{+}+{\mathrm{ClO}}^{-}\mathrm{ }$

$\therefore {\mathrm{HClO}}_4$ is more acidic then $\mathrm{HClO}.$

(ii)   ${\mathrm{Cl}}_2+{\mathrm{H}}_2\mathrm{O}\to \mathrm{HClO}+\mathrm{HCl}\mathrm{ }$

(iii)  ${\mathrm{HClO}}_4$ The central atom is ${\mathrm{sp}}^3$ hybridised.

 The central atom is ${\mathrm{sp}}^3$ hybridised.

(iv)  ${\mathrm{HClO}}_4+{\mathrm{H}}_2\mathrm{O}\to {\mathrm{H}}_3{\mathrm{O}}^{\oplus }+{\mathrm{ClO}}_4^{-}$ since ${\mathrm{H}}_2\mathrm{O}$ is accepting ${\mathrm{H}}^{+}$ from ${\mathrm{HClO}}_4$ so ${\mathrm{H}}_2\mathrm{O}$  is stronger base compare to ${\mathrm{ClO}}_4^{-}$.