Chemistry - Complete Pblock- Question with Solution | TestHub

When chlorine gas reacts with hot and concentrated $\mathrm{NaOH}$ solution, it disproportionates into chloride $\left({\mathrm{Cl}}^{-}\right)$and chlorate $\left({\mathrm{ClO}}_3^{-}\right)$ions.
In this process, oxidation number of chlorine changes from 0 to -1 and 0 to +5 . Note In disproportionation reactions, the same element undergoes oxidation as well as reduction.