SiCl 4 on hydrolysis forms ' X ' and HCl . Compound ' X ' loses water at 100 0 ∘ C and gives 'Y'. Compounds ' X ' and ' Y 'respectively are

SiCl 4 + 4 H 2 O ⟶ H 4 SiO 4 + 4 HCl H 4 SiO 4 100 0 ∘ C SiO Δ SiO 2 + 2 H 2 O

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Chemistry - Complete Pblock- Question with Solution | TestHub

ChemistryComplete Pblock-p-Block 13,14Medium2 minPYQ_2009

ChemistryMediumsingle choice

$SiCl_{4}$ on hydrolysis forms ' $X$ ' and $HCl$ . Compound ' $X$ ' loses water at $100 0^{\circ} C$ and gives 'Y'. Compounds ' $X$ ' and ' $Y$ 'respectively are

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Answer:

Solution:

$SiCl_{4} + 4 H_{2} O ⟶ H_{4} SiO_{4} + 4 HCl$ $H_{4} SiO_{4} 100 0^{\circ} C SiO Δ SiO_{2} + 2 H_{2} O$

Stream:VITEEESubject:ChemistryTopic:Complete Pblock-Subtopic:p-Block 13,14

⏱ 2mℹ️ Source: PYQ_2009

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