Chemistry - Complete Pblock- Question with Solution | TestHub

${\mathrm{SnCl}}_2$ (stannous chloride) on reaction with mercuric chloride $\left({\mathrm{HgCl}}_2\right)$, oxidises to ${\mathrm{SnCl}}_4$ (stannic chloride ) $${\mathrm{SnCl}}_2+2{\mathrm{HgCl}}_2\to {\mathrm{SnCl}}_4+{\mathrm{Hg}}_2{\mathrm{Cl}}_2$$ (Greyish) So in this reaction, stannous chloride is acting as reducing agent that reduces $\mathrm{Hg}$ (II) to $\mathrm{Hg}$ (I) and then to $\mathrm{Hg}(0)$ $${\mathrm{SnCl}}_2+{\mathrm{Hg}}_2{\mathrm{Cl}}_2\to 2\mathrm{Hg}+{\mathrm{SnCl}}_4$$