8 NH 3 + 3 Cl 2 ⟶ x + 6 NH 4 Cl (Excess ) NH 3 + 3 Cl 2 → y + 3 H Cl (Excess) Then the correct option(s) is/are :

Chemistry - Complete P-block Question with Solution | TestHub

ChemistryComplete P-blockp-Block 15,16Medium2 minQB

ChemistryMediummultiple choice

$8 NH_{3} + 3 Cl_{2} ⟶ x + 6 NH_{4} Cl$

(Excess )

$NH_{3} + 3 Cl_{2} \to y + 3 H Cl$

(Excess)

Then the correct option(s) is/are :

Answer:

B, D

Solution:

$8 N H_{3} + 3 C l_{2} ⟶ N_{2} + 6 N H_{4} Cl$

(Excess)

$N H_{3} + 3 C l_{2} ⟶ NC l_{3} + 3 H Cl$

(excess)

Stream:JEESubject:ChemistryTopic:Complete P-blockSubtopic:p-Block 15,16

⏱ 2mℹ️ Source: QB

Loading discussions...