When a molecule with μ = 1 Debye is placed near to a molecule with μ = 0 debye at the separation distance of 0.3 nm , then interaction energy is about 0.8 kJ/mole. Select CORRECT about above interacti

Question

When a molecule with μ = 1 Debye is placed near to a molecule with μ = 0 debye at the separation distance of 0.3 nm , then interaction energy is about 0.8 kJ/mole. Select CORRECT about above interaction.

TestHub · Accepted Answer

This is a dipole-induced dipole interaction, so it depends on the polarizability of the μ = 0 molecule and varies as 1/r⁶; for r = 0.3 nm the separation-distance contribution is about 10⁶⁰/729 in SI unit.

It is temperature-independent and is not a Keesom interaction.

Correct: (A), (B), (C).

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Options:(select one or more)

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