These questions contains, Statement I (assertion) and Statement II (reason).
Statement-1: Ozone is a stronger oxidizing agent in acidic medium.
Statement-2: $O_{3} + 2 H^{+} + 2 e^{-} \to O_{2} + H_{2} O$ ; SRP = $+ 2.07 V$
$O_{3} + H_{2} O + 2 e^{-} \to O_{2} + 2 O H^{-}$ ; SRP = $+ 1.24 V$

Question

These questions contains, Statement I (assertion) and Statement II (reason).

Statement-1: Ozone is a stronger oxidizing agent in acidic medium.

Statement-2: $O_{3} + 2 H^{+} + 2 e^{-} \to O_{2} + H_{2} O$ ; SRP = $+ 2.07 V$

$O_{3} + H_{2} O + 2 e^{-} \to O_{2} + 2 O H^{-}$ ; SRP = $+ 1.24 V$

TestHub · Accepted Answer

Question Explanation:

Evaluating the oxidizing power of Ozone based on Standard Reduction Potential (SRP).

Concept:

Electrochemical Series and Oxidizing Nature of Ozone.

Solution:

The oxidizing power of a substance is directly proportional to its Standard Reduction Potential (SRP) value. A higher positive SRP indicates a stronger tendency to gain electrons (get reduced), making it a stronger oxidizing agent.

Acidic Medium: $O_{3} + 2 H^{+} + 2 e^{-} \to O_{2} + H_{2} O; E^{\circ} = + 2.07 V$

Alkaline Medium: $O_{3} + H_{2} O + 2 e^{-} \to O_{2} + 2 OH^{-}; E^{\circ} = + 1.24 V$

Since $+ 2.07 V > + 1.24 V$ , the oxidizing power is greater in acidic medium.

Final Answer: Option (A)

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Options:

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