Consider the following covalent compounds in their SOLID state and find the value of (X + Y + Z) : PCl₅, PBr₅, N₂O₅, Cl₂O₆, XeF₄, XeF₂ X = total number of compounds in which the central atom of the ca

Question

Consider the following covalent compounds in their SOLID state and find the value of (X + Y + Z) :

PCl₅, PBr₅, N₂O₅, Cl₂O₆, XeF₄, XeF₂

X = total number of compounds in which the central atom of the cationic or anionic part is sp³ hybridised.

Y = total number of compounds having a 90° bond angle either in the cationic or anionic part.

Z = total number of compounds having a 109°28' bond angle either in the cationic or anionic part.

TestHub · Accepted Answer

Solid forms: PCl₅ = [PCl₄]⁺[PCl₆]⁻ ; PBr₅ = [PBr₄]⁺Br⁻ ; N₂O₅ = [NO₂]⁺[NO₃]⁻ ; Cl₂O₆ = [ClO₂]⁺[ClO₄]⁻ ; XeF₄ = square planar ; XeF₂ = linear.

X (sp³ centre): [PCl₄]⁺, [PBr₄]⁺, [ClO₄]⁻ → 3. Y (90°): [PCl₆]⁻ and XeF₄ → 2. Z (109°28'): [PCl₄]⁺, [PBr₄]⁺, [ClO₄]⁻ → 3. X + Y + Z = 8.

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